Questions tagged [common-root]

This tag is for questions containing common root(s) between two or more polynomial equations.

29 questions
11
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4 answers

Find a such that $ax^{17}+bx^{16}+1$ is divisible by $x^2-x-1$.

Find $a$ such that $ax^{17}+bx^{16}+1$ is divisible by $x^2-x-1$. I tried taking the roots of the polynomial which are $\frac{1±\sqrt{5}}{2}$ And I got the equation $a(\frac{1±\sqrt{5}}{2})^{17}+b(\frac{1±\sqrt{5}}{2})^{16}+1=0$ Now I don't know…
Toshu
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6
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1 answer

On the joint numerical range of a pair of symmetric matrices

Proposition 13.4 of Alexander Barvinok's A Course in Convexity shows the existence of the following result: Let $n\ge 3$. For two $n\times n$ symmetric matrices $A$ and $B$, and a PSD matrix $X$ with $\mbox{trace}(X) = 1$, there exists a unit…
6
votes
1 answer

Common roots of recursive defined polynomial

I have a series of polynomials $P_j(x)$ given by the recursive formula $$P_{j+1}=\frac{e_j}{c_j}xP_{j}-\frac{f_j}{c_j}P_{j-1} $$ with $P_{-1} \equiv 0$, $P_0 \equiv 1$, where $$c_j = (j+1)(j+2\kappa+1),\\ e_j = (2j+2\kappa+1)(j+\kappa+1),\\ f_j =…
6
votes
3 answers

Common complex roots

If the equations $ax^2+bx+c=0$ and $x^3+3x^2+3x+2=0$ have two common roots then show that $a=b=c$. My attempts: Observing $-2$ is a root of $x^3+3x^2+3x+2=0\implies x^3+3x^2+3x+2=(x+2)(x^2+x+1)=0$ Hence $ax^2+bx+c=0$ can have complex roots in…
mnulb
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4
votes
2 answers

If a quadratic equation can have real and equal roots, then why don't we say it has one root?

Suppose $ax^2+bx+c$ is a quadratic equation with $D=0$ So it has the roots $x=\frac{-b}{2a},\frac{-b}{2a}$ which are real and equal Why don't we just say it has one root which would be $x=\frac{-b}{2a}$?
3
votes
2 answers

numerically solving a system of multivariate polynomials

I have a system of polynomial equations which I need to solve numerically. The one Im currently interested in has around 20 variables and a similar number of equations. All coefficients are rational numbers. In the end I am only interested in real…
3
votes
1 answer

Common root of cubic and quadratic equation

If equations $ax^3+2bx^2+3cx+4d=0$ and $ax^2+bx+c=0$ have a non zero common root, prove that $(c^2-2bd)(b^2-ac) \geq 0$. I know the condition of common root of two quadratic equations but I have no idea on how to proceed with this question.
user600016
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3
votes
1 answer

Common roots of irreducible polynomials

Is it possible for two distinct irreducible polynomials with integer coefficients to have a root in common? In other words, is it possible that a root is shared by some two distinct irreducible polynomials? I would say no, because then it could be…
Ecir Hana
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2
votes
2 answers

Two quadratic equations having a common root

If quadratic equations $a_1x^2+b_1x+c_1=0$ and $a_2x^2+b_2x+c_2=0$ have both their roots common, then they satisfy $$\frac{a_1}{a_2}=\frac{b_1}{b_2}=\frac{c_1}{c_2}$$ But even if both the quadratic equations have only one common root(say $\alpha$),…
marks_404
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2
votes
0 answers

Roots with same size for polynomials with distinct degrees

I am working on a problem which just arrived at the following question related to roots of polynomials. Let $f(x)=x^7-2x^6+1$ and $g(x)=x^{10}-2x^9+1$. These polynomials have $x=1$ as their unique common root (because $f(x)/(x-1)$ and $g(x)/(x-1)$…
2
votes
0 answers

Find a polynomial $f \in \mathbb{Q}[x]$ with the least possible degree s.t. $\gcd(f,f')= x^5-5x^4+\frac{25}{4}x^3, f(1)=3$

We know that $f,f'$ have exactly the same roots their gcd has (and that $f'$ also matches their multiplicity). These are $x=0$ with multiplicity $3$ and $x=\frac{5}{2}$ with multiplicity $2$. Therefore, accounting for the increment in multiplicity,…
2
votes
2 answers

Is the following reasoning right?

I saw this post on Reddit and it had the following comment √x²=|x| It's the principle square root solution. So the square root of 49 is 7. It's the definition of square root. However the equation x²=7² has two solutions +7 & -7 Only because…
penguin99
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1
vote
1 answer

Common root of two equation

If the root of the equation 3x³+Px³+Qx-37=0 are each one more than the roots of the equation x³-Ax²+Bx-C, where A,B,C,P & Q are constants, then the value of A+B+C is equal to : Actually I solved this question by let a root of 3x³+Px³+Qx-37=0 is t…
Soni
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1
vote
1 answer

Solution verification on a question about polynomials and the midpoints of their intersection

Could someone check my solution to the following question? The above image describes the curve $y=x-x^3$ and the line $f(x)=m(x-p)+p-p^3$ where $m$ is the gradient of the line and $p<-1$. The two curves intersect at points $P(p,p-p^3), Q$ and $R$.…
1
vote
1 answer

Why do we need Bezout's Theorem in this statement?

I'm analyzing a paper concerning algebraic geometry. In a proof, author uses Bezout's theorem. But I don't get it much. Here is the summary: Let $K(t,s)$ and $F(t,s)$ be polynomials in $t,s$ with $F$ irreducible. The zero set of $K$ includes the…
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