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If equations $ax^3+2bx^2+3cx+4d=0$ and $ax^2+bx+c=0$ have a non zero common root, prove that $(c^2-2bd)(b^2-ac) \geq 0$.

I know the condition of common root of two quadratic equations but I have no idea on how to proceed with this question.

Rócherz
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user600016
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1 Answers1

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You can multiply the second by $x$ and subtract from the first. That leaves $(2b-a)x^2+(3c-b)x+(4d-c)=0$ and $ax^2+bx+c=0$ as two quadratic equations, which you know how to handle.

Ross Millikan
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  • how can subtraction give common roots? Any logic behind there. I came accross people subtract Biquadratic and cubic for common root l... but why? – mathophile Jul 13 '20 at 00:35