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This time I type my problem into LaTeX, but to show the problem I'll also include the appropriate snippet:

I do not understand in the book by Ralston: A first course in numerical analysis $(4.10-28)$ why

$$\Sigma_{j=0}^m |c_{mj}|=t_m(-1):$$

I would understand it if $c_{mj}$ alternate their signs,starting with positive for $j=0$, but I do not know why this is the case.

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user122424
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1 Answers1

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So your question is, if $x_1,...,x_n$ are positive real numbers and $$ p(z)=\sum c_kz^k=(x_1-z)(x_2-z)...(x_n-z), $$ if then the coefficient sequence is alternating. This is quite easy to see, as in the expansion of $$ p(-z)=\sum c_k(-1)^kz^k=(x_1+z)(x_2+z)...(x_n+z) $$ all coefficients are positive.

Lutz Lehmann
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