Questions tagged [covering-spaces]

For questions about or involving covering spaces in algebraic topology.

Let $\pi : E \to B$ be a continuous surjective map between topological spaces $E$ and $B$. We say that $\pi$ is a covering map if for every $x \in B$, there is an open neighbourhood $U$ of $x$ such that $\pi^{-1}(U)$ is a union of disjoint open sets in $E$, each of which is mapped homeomorphically onto $U$ by $\pi$.

We call $E$ a covering space of $B$ and often refer to $B$ as the base space.

The open neighbourhoods referred to in the definition are often called evenly covered neighbourhoods.

The fibres of $\pi$ are homeomorphic, so they all have the same cardinality; this cardinality is often called the number of sheets of the covering.

Reference: Covering space.

1820 questions
59
votes
3 answers

When is a local homeomorphism a covering map?

if $X$ and $Y$ are Hausdorff spaces, $f:X \to Y$ is a local homeomorphism, $X$ is compact, and $Y$ is connected, is $f$ a covering map? It seems to be, and I almost have a proof, but I'm stuck at the very end of it: I've already proved that $f$ is…
Or Sharir
  • 793
59
votes
1 answer

Why do all the Platonic Solids exist?

In three dimensions it is quite easy to prove that there exist at most five Platonic Solids. Each has to have at least three polygons meeting at each vertex, and the angles of these polygons have to add up to less than $2\pi$. This narrows down the…
46
votes
4 answers

Prove that there is a two-sheeted covering of the Klein bottle by the torus

Prove that there is a two-sheeted covering of the Klein bottle by the torus. OK, so we take the the polygonal representation of the torus and draw a line in the middle as follows: Then there are two Klein bottles in there, but how do I write down…
33
votes
5 answers

Covering spaces - why are they useful?

As someone who trained as a physicist, I have known for ages that $\operatorname{SU}(2)$ is a double cover of $\operatorname{SO}(3)$, so, during an idle day at the office I decided to look up what this meant. It turned out to be more complicated…
32
votes
1 answer

Do Lie algebras "know" about their Lie groups?

An undergraduate in physics asked me this question, and I did not know the answer, so I thought I would ask here. It is well-known that the Lie algebra to a Lie group is the tangent space to the identity of the group. Furthermore, via the…
A. Thomas Yerger
  • 18,175
  • 4
  • 45
  • 93
31
votes
1 answer

Find all connected covering space of $\mathbb RP^2\vee \mathbb RP^2$

This is exercise 1.3.14 in page 80 of Hatcher's book Algebraic topology. It's equivalent to consider subgroups of $\pi_1(X_1\vee X_2)=\mathbb Z_2 * \mathbb Z_2 =\langle a \rangle *\langle b \rangle$. To move this question out of the unanswered list,…
28
votes
2 answers

Universal cover via paths vs. ad hoc constructions

I'm looking for some intuition regarding universal covers of topological spaces. $\textbf{Setup:}$ For a topological space $X$ with sufficient adjectives we can construct a/the simply connected covering space of it by looking at equivalence classes…
28
votes
2 answers

Deck transformations of universal cover are isomorphic to the fundamental group - explicitly

I have read on several places that given a (say path connected) topological space $X$ and its universal covering $\tilde{X}\stackrel{p}\rightarrow X$, there is an isomorphism $$\mathrm{Deck}(\tilde{X}/X) \simeq \pi_1(X, x_0).$$ Here…
27
votes
3 answers

Is every closed simply connected manifold a non-trivial covering space?

We know that every universal covering space is simply connected. The converse is trivially true, every simply connected space is a covering space of itself. But I'm wondering what simply connected spaces, specifically manifolds, are covering spaces…
Paul Cusson
  • 2,175
24
votes
6 answers

Homology Whitehead theorem for non simply connected spaces

(One version of) the Whitehead theorem states that a homology equivalence between simply connected CW complexes is a homotopy equivalence. Does the following generalisation hold true? Suppose $X,Y$ are two connected CW complexes and $f:X\to Y$ is a…
20
votes
1 answer

Show that if B is simply-connected, then p is a homeomorphism.

Let $p: E \rightarrow B$ be a covering map with $E$ path-connected. Show that if $B$ is simply-connected, then $p$ is a homeomorphism. I'm checking to see if my solution is flawed. Since $p$ is a covering map it is a continuous, surjective and open…
EgoKilla
  • 2,568
20
votes
2 answers

Why is the Long Line not a covering space for the Circle

I know of several reasons why the long line can't be a covering space for the circle, but I'm more curious in what exactly goes wrong with the following covering map. Let $L$ be the long line and define $p: L \rightarrow \mathbb S^1$ by wrapping…
JSchlather
  • 15,745
20
votes
1 answer

Can two different topological spaces cover each other?

I.e. do there exist non-homeomorphic $X$, $Y$ and covering maps $f:X\rightarrow Y$, $g: Y\rightarrow X$? I have a basic understanding of covering space theory as its taught in school. I was inspired by this question Two covering spaces covering each…
19
votes
1 answer

A good way to understand Galois covering?

A covering map $f:X\rightarrow Y$ is called Galois if for each $y\in Y$ and each pair of lifts $x, x^{'}$, there is a covering transformation taking $x$ to $x^{'}$. What is a good way to understand this definition? It seems to me that $f$ is Galois…
M. K.
  • 5,191
  • 2
  • 33
  • 55
18
votes
4 answers

Local homeomorphisms which are not covering map?

I am trying to find examples of maps between topological space which are local homeomorphism but not covering maps. Especially, how twisted has to be such a counterexample : can it be a local diffeomorphism between connected manifolds which is not a…
1
2 3
99 100