How can we show that every automorphism of $S_4$ is an inner automorphism ?
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What are the index 4 subgroups of $S_4$? – Robin Chapman Nov 04 '10 at 15:48
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See https://math.stackexchange.com/questions/880776/operatornameauts-4-is-isomorphic-to-s-4 – bfhaha Oct 28 '18 at 21:11
2 Answers
Note that:
Any automorphism preserves the conjugacy class of transpositions.( By counting size of conjugacy classes)
Any automorphism preserves whether two transpositions share an element (by looking at the order of their product)
Any automorphism permutes the four classes of transpositions {those that move 1}, {those that move 2}, {those that move 3}, {those that move 4}
This gives you a permutation on {1,2,3,4} and it is not hard to show that your automorphism is conjugation by this permutation
Automorphisms send conjugacy classes to conjugacy classes and preserve elements' order. In $S_4$, distinct conjugacy classes have elements of distinct orders except the conjugacy classes of the transpositions and the double transpositions (both whose elements have order $2$); but the former has size $6$, whilst the latter has size $3$, so no one automorphism can swap them. Therefore, every automorphism is cycle type-preserving, and then inner.
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