If you have a tableau proof for $\Box A$, Show that there is also a tableau proof for A.
Here is my attempt but I'm not sure if it's correct:
If we have a tableau proof for $\Box A$, it means that all possible worlds that are accessible from the current world satisfy $A$. Therefore, if we can show that there is at least one world that satisfies $A$ in the current world, then $A$ must be true.
To show this, we can take the original tableau proof for $\Box A$ and add an additional branch where we assume $\neg A$. Then, we can apply the $\Box$ rule to this branch, which will generate a contradiction, since we know that all accessible worlds satisfy $A$. This contradiction allows us to close the branch and conclude that $A$ must be true in the current world.