How do I solve this integral?
$$\int_0^1 \frac {x^4 (1-x)^4}{x^2+1} dx$$
How do I solve this integral?
$$\int_0^1 \frac {x^4 (1-x)^4}{x^2+1} dx$$
The first thing I would notice that this a "rational" function and that the numerator has higher degree than the denominator so we can divide to get a polynomial plus a rational function with denominator of higher degree than the numerator.
If I have done the algebra correctly $\frac{x^4(1- x)^4}{x^2+ 1}= x^6- 4x^5+ 5x^4- 4x^2+ 4+ \frac{-3}{x^2+ 1}$
It should be easy to integrate that.