Given the totient summatory function
$$\Phi(x)=\sum\limits_{n=1}^x\varphi(n)\tag{1}$$
and the related Dirichlet series
$$\frac{\zeta(s-1)}{\zeta(s)}=\underset{N\to\infty}{\text{lim}}\left(\sum\limits_{n=1}^N\frac{\phi(n)}{n^s}\right)\,,\quad\Re(s)>2\tag{2}$$
the explicit formula for
$$\Phi_o(x)=\underset{\epsilon\to 0}{\text{lim}}\left(\frac{\Phi(x-\epsilon)+\Phi(x+\epsilon)}{2}\right)\tag{3}$$
derived from the residues at the poles of
$$\frac{\zeta(s-1)}{\zeta(s)}\,\frac{x^s}{s}\tag{4}$$
is
$$\Phi_o(x)=\frac{3\,x^2}{\pi^2}+\underset{T\to\infty}{\text{lim}}\left(\sum\limits_{|\Im(\rho)|\le T}\frac{x^\rho\,\zeta(\rho-1)}{\rho\,\zeta'(\rho)}\right)+\frac{1}{6}+\underset{N\to\infty}{\text{lim}}\left(\sum\limits_{n=1}^N\frac{x^{-2\,n}\,\zeta(-2\,n-1)}{(-2\,n)\,\zeta'(-2\,n)}\right)\tag{5}$$
where $\rho$ is a non-trivial zero of $\zeta(s)$.
I've been told the explicit formula for $\Phi_o(x)$ defined in formula (5) above doesn't converge.
Peter Humphries explains the reason for this in a comment on my my related question.
The explicit formula for $\sum_{n \leq x} \varphi(x)$ is wrong; when you shift the contour, the shifted contour integral is not small. One can use this to show that the error term for this sum is at least as large as a constant multiple of $x\sqrt{\log \log x}$ infinitely often.
Peter provides further clarification in another comment.
What I mean is that $\sum_{n \leq x} \varphi(x)$ has a main term, coming from the pole of $\zeta(s - 1)/\zeta(s)$ at $s = 2$, and an error term of size at least $x\sqrt{\log \log x}$, which does not come from the poles of $\zeta(s - 1)/\zeta(s)$ at the zeroes of $\zeta(s)$.
Note that in the two comments quoted above $\varphi(x)$ should have been $\varphi(n)$.
Question (1):
Given the summatory function
$$f(x)=\sum\limits_{n=1}^x a(n)\tag{6}$$
and assuming the related Dirichlet series
$$F(s)=\underset{N\to\infty}{\text{lim}}\left(\sum\limits_{n=1}^N\frac{a(n)}{n^s}\right)\,,\quad\Re(s)>\alpha\ge 2\tag{7}$$
doesn't converge at $\Re(s)=2$, is it true in general that the explicit formula for
$$f_o(x)=\underset{\epsilon\to 0}{\text{lim}}\left(\frac{f(x-\epsilon)+f(x+\epsilon)}{2}\right)\tag{8}$$
derived from the residues at the poles of
$$F(s)\,\frac{x^s}{s}\tag{9}$$
doesn't converge?
Question (2):
Assuming the answer to Question (1) above is yes, is $2$ a special number or can $2$ in question (1) above be replaced with some $\lambda$ where $1<\lambda<2$ where the answer to the modified question would still be yes?
Question (3):
Assuming the answer to Question (2) above is no:
Question (3a): What is an example of an explicit formula that converges associated with the conditions stated in Question (1) above?
Question (3b): Can $2$ in question (1) above be replaced with some $\lambda$ where $\lambda>2$ where the answer to the modified question would be yes?