What is the area of the largest equilateral triangle which fits inside a square of side a?
so area of trinagle is $\frac{a^2}{2}$, however it is wrong, why ?
What is the area of the largest equilateral triangle which fits inside a square of side a?
so area of trinagle is $\frac{a^2}{2}$, however it is wrong, why ?
Hint. Place one vertex of the triangle on one of the corners of the square, and the other two vertices symmetrically placed on the opposite neighbouring sides of the square