the circle group is the multiplicative group of all complex numbers of absolute value 1. How can i show that this group is isomorphic with $\mathbb R/ \mathbb Z$. Any hints for the right map is great.
Asked
Active
Viewed 2,229 times
7
-
See also http://math.stackexchange.com/questions/274841/show-that-mathbbr-mathbbz-is-isomorphic-to-ei-theta-0-le-theta – Martin Sleziak Oct 31 '16 at 09:15
2 Answers
7
The map $\phi\colon\Bbb R\to T$ given by $\phi(t)=e^{2\pi it}$ is a group morphism. Hence we can apply first isomorphism theorem.
Davide Giraudo
- 181,608