If I properly understand, you are looking for a way to compute $i$ in the formula $$A=P\frac{i \,(i+1)^n}{(i+1)^n-1}$$ There is no analytical formula and you could find some approximations here. So, consider that you need to find the zero of the equation $$f(i)=P\frac{i \,(i+1)^n}{(i+1)^n-1}-A$$ Use Newton method which, starting from one of the guesses $i_0$ given in the link, will update it according to $$i_{k+1}=i_k-\frac{f(i_k)}{f'(i_k)}$$ using $$f'(i)=P\frac{(i+1)^{n-1} \left((i+1)^{n+1}-i( n+1)-1\right)}{\left((i+1)^n-1\right)^2}$$ It will converge very quickly to the solution.
Using your numbers, the simplest estimate (called $i_1$ in the link) is $\frac{357}{38125}$ and the successive iterates of Newton method will be $$0.00864101$$ $$0.00863680$$ which is the solution for six significant figures.
All of that is easily doable with Excel.