What is the following command "typedef mpc_val_t(mpc_apply_t)(mpc_val_t*);"

Question

Can someone provide an explanation of the following command?

typedef mpc_val_t*(*mpc_apply_t)(mpc_val_t*);

`mpc_apply_t` is declared as a name for the type "pointer to function taking `mpc_val_t*` and returning `mpc_val_t*`" — Igor Tandetnik, May 28 '21 at 23:19

score 1 · Accepted Answer · answered May 28 '21 at 23:23

1

This is a type definition for mpc_apply_t, defining it as a pointer to a function accepting a pointer to a value of type mpc_val_t, and returning a pointer to a value of type mpc_val_t. The type mpc_val_t is defined elsewhere.

answered May 28 '21 at 23:23

Jan Pokorný

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What is the following command "typedef mpc_val_t*(*mpc_apply_t)(mpc_val_t*);"

1 Answers1

What is the following command "typedef mpc_val_t(mpc_apply_t)(mpc_val_t*);"