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I have the following case. In jenkins I have one build which is running on different envoironments. That's why I have build with parameters with two options PROD/TEST. The build is invoking shell script with parameter PROD or TEST.

Here is example of the script A which jenkins is invoking:

if %1%==TEST(
start F:\test.bat
 )

The script A itself is invoking another script - B.

Here is example of script B:

copy test.xt copyFolder\

The problem is that Jenkins only invoking the first script - A - and the second script B doesn't run.

Why does this happen?

Compo
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Svetoslav Angelov
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1 Answers1

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You will need to call the batch file, not start it because it creates a new cmd.exe instance, so it can run a called batch file asynchronously (as mentioned by jeb here):

if "%~1" == "TEST" (
    call F:\test.bat
)

Here, I want to note some things:

  • %1% will be interpreted as the first argument of the batch file (if any) and an extra percent-sign (%). You probably wanted here the first argument, so I have replaced %1% with %1. If it is not this what you wanted, then replace it with your variable name, but remember that it should not start with a number!
  • %1 was replaced by %~1 and quoted because:
    • %~1 means the first argument without any surrounding quotes.
    • Quoting the values in an if statement is always the best practice, but if there were quotes, the comparison would fail.
  • Added a space between ==, just to make the code clearer.

For an one-liner, see aschipfl's comment, it is:

if /I "%~1"=="TEST" (call "F:\test.bat")

See call /? and if /? in cmd for more information about how these commands work.

double-beep
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