Modifying inner reader in a transformer stack

Question

I'm pulling together code from a number of different places, and I'm trying to deal with the following:

Problem

I have a transformer stack with the following simplified type:

action :: m (ReaderT r IO) a

and I'm trying to use the action in the context of a different stack, which has a different reader environment:

desired :: m (ReaderT r' IO) a

I can of course provide

f :: r' -> r

Example

things :: m (ReaderT r' IO) ()
things = do
   -- ... some stuff

   -- <want to use action here>
   action :: m (ReaderT r IO) a -- broken

    -- ... more stuff
   pure ()

What I've considered

withReaderT :: (r' -> r) -> ReaderT r m a -> ReaderT r' m a

This has the problem that ReaderT is the outer monad, whilst I want to use it on an inner one.

I've also considered that this might be related to MonadBase or MonadTransControl, but I'm not familiar with their workings.

Have you seen https://hackage.haskell.org/package/mmorph-1.1.0/docs/Control-Monad-Morph.html? If you provide `ReaderT r m a -> ReaderT r' m a`, `hoist` from `MFunctor` can do what you want. — Juan Pablo Santos, Sep 06 '17 at 17:07
Whether you can do this also depends on `m`. For example this is not possible with `ContT`. — Li-yao Xia, Sep 06 '17 at 20:44
Indeed. Checkout the instances for `MFunctor` for more details. — Juan Pablo Santos, Sep 07 '17 at 16:41

score 5 · Accepted Answer · answered Sep 06 '17 at 21:20

I don't think it's possible to write a function with signature:

changeReaderT :: (MonadTrans m)
                 => (r -> r') 
                 -> m (ReaderT r IO) a 
                 -> m (ReaderT r' IO) a

the issue being that the only operation possible, in general, on the second argument is lifting it to t (m (ReaderT r IO)) a for some monad transformer t, which doesn't buy you anything.

That is, the MonadTrans m constraint alone doesn't provide enough structure to do what you want. You either need m to be an instance of a typeclass like MFunctor in the mmorph package that allows you to modify an inner layer of the monad stack in a general way by providing a function like:

hoist :: Monad m => (forall a. m a -> n a) -> t m b -> t n b

(which is what @Juan Pablo Santos was saying), or else you need an ability to dig into the structure of your m monad transformer to partially run and rebuild it (which will be transformer-specific).

The first approach (using hoist from the mmorph package) will be most convenient if your m is already made up of transformers supported by the mmorph package. For example, the following typechecks, and you don't have to write any instances:

type M n = MaybeT (StateT String n)

action :: M (ReaderT Double IO) a
action = undefined

f :: Int -> Double
f = fromIntegral

desired :: M (ReaderT Int IO) a
desired = (hoist $ hoist $ withReaderT fromIntegral) action

You'll need a hoist for each layer in M.

The second approach avoids hoist and requisite MFunctor instances but requires tailoring to your specific M. For the above type , it looks something like:

desired' :: M (ReaderT Int IO) a
desired' = MaybeT $ StateT $ \s ->
  (withReaderT fromIntegral . flip runStateT s . runMaybeT) action

You basically need to run the monad down to the ReaderT layer and then rebuild it back up, treating layers like StateT with care. This is exactly what the MFunctor instances in mmorph are doing automatically.

Modifying inner reader in a transformer stack

Problem

Example

What I've considered

1 Answers1