int a = 3;
auto f = [a] (int a) { return a > a; }
Q：capture the local variable names a and lambda have a differentiated method?
I think it is within the scope of a parametric a is independent of the external local variables a, would like to know whether there is something like this pointer distinction.
When the compiler processes a lambda, what it does is basically create a special class that it instantiates. The actual lambda function becomes a operator() function, and the captured variables becomes member variables in this special class.
That means the normal scoping rules apply, where local variables and arguments shadows member variables.
So in your case a is the argument, not the captured variable.
