Assign input form to a variable

Question

I have this input form which goes like this:

<input type="checkbox" name="vehicle" value="Bike" />

I want to print it inside this variable:

$return .= '<div class="flink">'.$checkbox.'</div>';

or can i assign it to any other variable?

How can i do it? I tried putting :

$checkbox.= '<input type="checkbox" name="vehicle" value="Bike" />';

Whats the issue here. You are doing it correct. Just echo the variable to output — Sabari, Jun 27 '12 at 12:35
In the last line there is no need of a dot in front of = sign just $checkbox = ''; — Sabari, Jun 27 '12 at 12:36
Hey Guys, i'm using . at the end because otherwise it wouldn't work! Well, i'm so sorry, it's just.. well, i was doing something else wrong. Everything's fine,, thanks ^^' — Albana, Jun 27 '12 at 12:37
`.=` is used to append a string to an existing string. `$x = "foo"; $x .= "bar"; echo $x;` will output `foobar` — Joe Flynn, Jun 27 '12 at 12:38

score 1 · Answer 1 · answered Jun 27 '12 at 12:37

1

Just add:

$return = '<div class="flink">'.$checkbox.'</div>';
echo $return; // Somewhere on the page.

It looks like you're defining it fine, you just may not be echoing it out on the page.

answered Jun 27 '12 at 12:37

MultiDev

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Hey, one question, i've got $return .= '
'.$link.'
'; how can i add even the $checkbox, to appear? – Albana Jun 27 '12 at 12:41

score 0 · Accepted Answer · answered Jun 27 '12 at 12:34

0

If you're looking to print a variable to the webpage, you can use several different commands.

The echo command is useful when the variable is HTML.
The var_dump command is useful for debugging purposes, as it works on all kinds of variables.
print_r is also nice, because it formats the output in a way that's readable.

answered Jun 27 '12 at 12:34

SomeKittens

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`$return .= '
'.$checkbox.$link.'
';` You can concatenate multiple strings in one command. Then use one of the print functions I linked to. – SomeKittens Jun 27 '12 at 12:40

score 0 · Answer 3 · answered Jun 27 '12 at 12:37

         <?php
                $q="select * from stores";
                $res=mysql_query($q);
                $StoreOPtion = '<option value="">--select--</option>';
                while($rs=mysql_fetch_object($res))
                 { 
                 $StoreOPtion .= '<option   value="'.$rs->StoreId.'||StoreName:'.$rs->StoreName.'..  Street:'.$rs->StoreStreet.'..Phone:'.$rs->StorePhone.'..Email:'.$rs->StoreEmail.'..Area:'.$rs->StoreArea.'..Pin:'.$rs->StorePincode.'">'.$rs->StoreName.'</option>';

                } 
                ?>
        <select name="StoreName" type="text" id="StoreName"  onchange="getStoreAdd()"/>
       <?php echo $StoreOPtion; ?>
         </select>

Here i am using dropdown box. ypu sehe this example and use it

Assign input form to a variable

3 Answers3

Linked