I want to calculate a double limit in Maxima. For instance,$$\lim_{(x, y)\to(0, 0)}\frac{x^3y}{x^6+y^2}$$
By the way, it is very interesting that I calculated it in "wolframalpha" yet it gave me the result $0$! I think the correct answer should be "does not exist": $$\lim_{(x, y)\to(0, 0)}\frac{x^3 y}{x^6+y^2}=\lim_{x\to0,\ y=kx^3\rightarrow0}\frac{kx^6}{x^6+k^2 x^6}=\frac{k}{1+k^2}$$Am I right? Anyway, how to do it in Maxima?
Thanks!
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zhaoyin.usm
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You're right. WolframAlpha doesn't indicate the existence of multivariable limit, I guess. – Math.StackExchange May 27 '14 at 12:18
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Looks like a sound argument! – Tom May 27 '14 at 12:28
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1But how to calculate in Maxima? Or the software cannot compute it? – zhaoyin.usm May 27 '14 at 12:48