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Let $p: Y \to X$ be a covering space and $X$ is connected. I want to show that $\forall x \in X$ the cardinality of $p^{-x}$ is the same.

$\textbf{My Attempt:}$ Let us first fix a point $x_0 \in X$ such that $|p^{-1}(x_0)|=\kappa$.

Then let $H=\{x \in X \mid |p^{-1}(x)=\kappa| \}$

Then let $f: H \to \text{Cardinals}$ be defined as

$f(x)=|p^{-1}(x)|$. Then $f$ is a constant function on $H$.

How do I show that $H$ is open? $H$ is the inverse image of $\{\kappa\}$ but this is a singleton set from the collection of cardinals. I am not really sure what to do with that.

If I can show that $H$ is open, then I can prove by contradiction, using the assumption of connectedness, that all $x \in X$ are such that $|p^{-1}(x)|= \kappa$.

user7090
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