There are standard answers to all three of your questions, if one assumes the axiom of choice (as is almost always done these days).
First, we have two reasonable definitions for what it means to say that cardinal $\alpha$ is greater than cardinal $\beta$. Say set $A$ has cardinality $\alpha$ and $B$ has cardinality $\beta$. If there is a one-one function from $B$ to $A$, then we say $\alpha\geq\beta$. Or alternately, if there is a function from $A$ onto $B$, then we say $\alpha\geq\beta$. Given the axiom of choice, one can prove that these are equivalent. (Also one can prove that these definitions do not depend on the choice of $A$ and $B$: if $A'$ and $B'$ also have cardinalities $\alpha$ and $\beta$, then you get the same results.)
We say that $\alpha=\beta$ if there is a one-one onto function from $A$ to $B$, and finally $\alpha>\beta$ if $\alpha\geq\beta$ but there is no one-one onto function from $A$ to $B$.
With these definitions, here are the answers (without proofs):
(a) Yes, every uncountable infinity is greater than every countable infinity.
(b) No, all countable infinities are the same: if $A$ and $B$ are both countable and infinite, then $\alpha=\beta$.
(c) Yes, some uncountable infinities are greater than others. For example, if $A$ is set of all functions from the real numbers to the real numbers, and $B$ is the set of real numbers, than $\alpha>\beta$.
However, the set of all reals between $x$ and $y$, $x<y$, has the same cardinality as the set of all reals. So intuition can be misleading.
Cantor proved in general that $2^\alpha>\alpha$ for any cardinal number $\alpha$. (Here, $2^\alpha$ is the cardinality of the set of all subsets of $A$.) So one can construct the so-called beth sequence: $$\beth_0=\aleph_0; \beth_1=2^{\beth_0}; \beth_2=2^{\beth_1}; etc.$$ and $$\beth_0<\beth_1<\beth_2<\ldots$$ Here, $\aleph_0$ is the cardinality of any infinite countable set.
Cantor also proved that for any cardinal $\alpha$, there is a next bigger cardinal: a cardinal $\alpha'>\alpha$, such that there are no cardinals strictly in-between $\alpha$ and $\alpha'$. So we also have the $\aleph$ sequence: $$\aleph_1=\aleph_0'; \aleph_2=\aleph_1'; \aleph_3=\aleph_2'; etc.$$ and $$\aleph_0<\aleph_1<\aleph_2<\ldots$$ The conjecture that the aleph sequence is the same as beth sequence is known as the Generalized Continuum Hypothesis (GCH). GCH cannot be proved or disproved from the usual axioms of set theory, leading to lots of philosophical discussion on the nature of mathematical reality.
There are arithmetical rules, but they are not what you might expect. If $\alpha\geq\beta$, and $\alpha$ is infinite, then $\alpha+\beta=\alpha$: the larger infinite cardinality "absorbs" all smaller (or equal) cardinalities. In fact, if $\alpha\geq\beta$, and $\alpha$ is infinite and $\beta\neq 0$, then $\alpha\cdot\beta=\alpha$.
To repeat, all this is assuming the axiom of choice, and omitting all proofs.
Kaplansky's Set Theory and Metric Spaces is a nice introduction to all this.
