Given the j-function $j(\tau)$ and elliptic lambda function $\lambda(\tau)$. Define,
$$g = -1+2\frac{\,_2F_1\big(\tfrac{1}{2},\tfrac{1}{2},1,\,\lambda(2\tau)\big) }{\,_2F_1\big(\tfrac{1}{2},\tfrac{1}{2},1,\,\lambda(\tau)\big) }$$
then,
$$j(\tau) = \frac{4^4(g^4-g^2+1)^3 }{(g^4-g^2)^2}\tag{1}$$
Question: Any other formula that uses $\,_2F_1\big(a,b;c;z\big)$ for other $a,b,c$?
$\color{blue}{Edit}$: (In response to ccorn's answer.)
For any non-zero constant $N(N-1728)\neq0$, one can solve the following two equations,
$$N = \frac{(x^2+10x+5)^3}{x}\tag{2}$$
$$N = \frac{-(r^{20} - 228r^{15} + 494r^{10} + 228r^5 + 1)^3}{r^5(r^{10} + 11r^5 - 1)^5}\tag{3}$$
for unknowns $x,r$ as,
$$x = \frac{-125r^5}{r^{10}+11r^5-1}$$
where,
$$r = \frac{N\,^{-11/60}\,_2F_1\left(\tfrac{31}{60},\tfrac{11}{60},\tfrac{6}{5},\tfrac{1728}{N}\right)}{N\,^{1/60}\,_2F_1\left(\tfrac{19}{60},\tfrac{-1}{60},\tfrac{4}{5},\tfrac{1728}{N}\right)} = \frac{(N-1728)^{-11/60}\,_2F_1\left(\tfrac{41}{60},\tfrac{11}{60},\tfrac{6}{5},\tfrac{1728}{1728-N}\right)}{(N-1728)^{1/60}\,_2F_1\left(\tfrac{29}{60},\tfrac{-1}{60},\tfrac{4}{5},\tfrac{1728}{1728-N}\right)}$$
The eqns (2) and (3) are the Jacobi sextic and icosahedral equation, respectively, both of which do not have a solvable Galois group. (Eq. (1) has a solvable group.)
The utility of the question is then it finds an equation, with one free parameter $N$ (the special case $N = j(\tau)$ being only a subset), that can be solved in terms of $_2F_1(a,b;c;z)$ where $z$ is a function of $N$. (This also implies the general quintic, via the Jacobi sextic, is solvable in terms of $r$.)
So it would be nice to find more polynomial examples like (1), but has a higher degree.