Inverse Laplace Transform : $\mathcal{L}^{-1} \left \{ 2\cdot s^{-1}\cdot e^{-3\cdot s} \right \}$

Question

I need to find the inverse laplace transform below. Is there any trick for this question? I tried but I couldnt find it.

$$\mathcal{L}^{-1} \left \{ 2\cdot s^{-1}\cdot e^{-3\cdot s} \right \}$$

Thanks in advance.

Here is a related problem. – Mhenni Benghorbal Dec 09 '13 at 07:00 — Mhenni Benghorbal, Dec 09 '13 at 07:00

score 3 · Accepted Answer · answered Dec 09 '13 at 06:51

3

Hint:

$$\mathscr{L}^{-1}\left\{ \frac{1}{s} \right\}=1=f(t)$$ and $$\mathscr{L}^{-1}\{e^{-as}F(s)\}=f(t-a)\mathscr{U}(t-a),~~a>0$$ where $a=3$.

answered Dec 09 '13 at 06:51

Mikasa

Thank you. Do you have any table or something for these equations? I didnt know this equation.It would be great. – g3d Dec 09 '13 at 06:55
@g3d: An elementary table would be this. – Mikasa Dec 09 '13 at 07:03
@B.S.: Very clear and concise +1 – Amzoti Dec 09 '13 at 14:13
I agree with Sami! +1 – amWhy Dec 09 '13 at 23:34

1 Answers1