What does it mean that a homomorphism preserves algebraic structure of a group ? What does it mean algebraic structure? Can someone please explain in simpler and detailed terms.
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If you have a homomorphism between groups $G$ and $G'$ then things (as in the binary operator) "works the same way" in both $G$ and $G'$". It doesn't matter if you use the binary operator on two elements from $G$ and then map the result to $G'$ or if you map two elements from $G$ to $G'$ and then use the binary operator from $G'$. The result will be the same. – John Smith Dec 06 '13 at 08:39
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This might be of interest http://math.stackexchange.com/questions/147632/isomorphisms-preserve-structure-operation-or-order?rq=1 – John Smith Dec 06 '13 at 08:47
1 Answers
The definition of a homomorphism $\varphi:G \to H$ for groups $G, H$ is given by the following axiom:
$\varphi(gg') = \varphi(g)\varphi(g')$ for $g,g' \in G$,
It can be shown that $\varphi(1_G) = 1_H$, the units of $G$ and $H$ respectively and $\varphi$ maps inverses to inverses by $\varphi(g^{-1}) = \varphi(g)^{-1}$
What do all of these mean? In the first axiom, our homomorphism takes the composition of any two elements in $G$ and sends it to the composition of two elements in $H$, $\varphi(g)$ and $\varphi(g')$. Furthermore, it preserves identity: $1_G$ is mapped to $1_H$ and it preserves inverses.
Hence, we can see that the homomorphism maintains the "group structure" by, in a sense, preserving the law of composition, identities, and inverses; the homomorphism is "translating" the structure of a group G to the structure of another group H.
When there exists a bijective homomorphism, an isomorphism, between two groups then we can consider the two groups nearly the same as they have the same properties; the homomorphism translating the properties of the first group to the ones of the second can be inverted, so there is little distinction between the two groups.
Disclaimer: I don't claim to be an expert, just throwing in my own insights
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Note that the implications of homomorphisms probably go much deeper than this, especially once one goes into branching fields. I haven't gotten any further than algebra myself, so I can't give you any examples, sorry. – Lost Dec 06 '13 at 08:39