I recently learned of the $\Pi$ symbol, and was wondering if the following is an accurate way to represent $n!$:
$\Pi_{i=0}^{n-1} n - i$
I recently learned of the $\Pi$ symbol, and was wondering if the following is an accurate way to represent $n!$:
$\Pi_{i=0}^{n-1} n - i$
Yes, apart from the missing parentheses: make it $$\prod_{i=0}^{n-1}(n-i)\;,$$ and you’ll be fine. As $i$ runs from $0$ up through $n-1$, $n-i$ runs from $n$ down through $n-(n-1)=1$, which is exactly what you want.