I need some help in calculating the length of a spiral helix wrapping a torus at a given angle. Real-world application: wrapping tape around a hula-hoop, calculating the length of tape used, given the thickness of the hoop, the circumference of the outside of the hoop, and the angle of wrapping.
Assume 0-degrees is the poloidal angle, and 90-degrees is the angle along the equator of the hoop.
Is this equation correct?
$L$ = length
$C$ = outer circumference of torus/hoop
$t$ = thickness of hoop
$ϕ$ = angle of wrapping helix
$$L = {C-{2 π(t/2)} \over \sin(ϕ)}.$$
EDIT: To clarify, the application is not attempting to completely cover the surface of the hoop with tape. Imagine a decorative tape that wraps the hoop at an angle (say $30°$), leaving a gap between each helictical go-round. At $90°$ degrees, the amount of tape used is equal to the hoop's outer circumference. At $0$, the amount of tape used is equal to the hoop material's thickness. Have I found the correct equation to calculate tape-length at various other angles?
helixcoil?) tape. That is wrong because a 90 degree wrap is the circumference of the hoop/torus, and wrapped-tape length should get longer as you decrease the wrapping angle, until it reaches the asymptote of 0 degrees (at which point tape length = tube thickness).So I've turned to human help. I'm not a mathematician, just someone looking for a practical use.
– Bryan Smith Jun 25 '25 at 02:13