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I found two terms:

  • Enveloping algebras, and
  • Universal enveloping algebras

I read the answer to the following question Universal enveloping algebra, but I am seeking more details and a connection between them, if possible.


As in An Introduction to Homological Algebra (Page 83), let $A$ be a $k$-algebra, where $k$ is a commutative ring, then its enveloping algebra is $$ A^e = A \otimes_k A^{\text{op}}. $$

In Enveloping Algebras (Page 66), let $\mathcal{T}$ be the tensor algebra of the vector space $\mathfrak{g}$ ($\mathfrak{g}$ is a Lie algebra), i.e. $$ \mathcal{T} = T^0 \oplus T^1 \oplus \dots \oplus T^n \oplus \dots, $$ where $T^n = \mathfrak{g} \otimes \mathfrak{g} \otimes \dots \otimes \mathfrak{g}$ ($n$ times); in particular, $T^0 = k \cdot 1$ and $T^1 = \mathfrak{g}$; the product in $\mathcal{T}$ is simply tensor multiplication.

Let $J$ be the two-sided ideal of $\mathcal{T}$ generated by the tensors $$ x \otimes y - y \otimes x - [x,y], $$ where $x, y \in \mathfrak{g}$. The associative algebra $\mathcal{T}/J$ is termed the universal enveloping algebra of $\mathfrak{g}$ and is denoted by $U(\mathfrak{g})$.


NB: I know that every associative algebra with additive $+$ and multiplicative $\times$ laws can be turned into a Lie algebra by defining the Lie bracket using them.

Thanks.

  • @MatthewTowers Thank you, can you please share some references? – The Student Apr 15 '25 at 13:16
  • Have you looked at this question? https://math.stackexchange.com/questions/3286377/universal-enveloping-algebra?rq=1 – aeae Apr 15 '25 at 14:52
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    Also look at https://math.stackexchange.com/q/4245114/96384 and https://math.stackexchange.com/q/1405568/96384 for the Lie algebra case. I do not think that "enveloping algebra" you found in your first source, which is not directly related to Lie algebras, is strongly related to that concept in that theory. People might use that term differently (I would have called any quotient of the universal enveloping algebra an enveloping algebra) in different contexts. – Torsten Schoeneberg Apr 15 '25 at 19:01

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