I was studying Krein-Milman Theorem in the aspect of infinite dimensional Banach spaces. We know that the closed unit ball $B_{X^*}=\{f\in X^*:\|f\|\leq 1\}$ of dual space $X^*$ of an infinite dimensional Banach space $X$ is convex and compact under weak-star topology. Then by applying Krein-Milman Theorem we have $B_{X^*}=\overline{\operatorname{conv}}^{weak^*}(E_{B_{X^*}})$, where $E_{B_{X^*}}$ is the collection of all extreme points of $B_{X^*}$.
Now, I am struggling with the following ideas:
$\textbf{(1)}$ What can be the formulation of a sequence in $\operatorname{conv}(E_{B_{X^*}})$?
$\textbf{(1.1)}$ Is it $\{\displaystyle{\sum_{i=1}^k} \lambda_i^{n}f_i\}_{n\in\mathbb{N}}$, where $f_i\in E_{B_{X^*}}$?
$\textbf{(1.2)}$ If so, then for any $f\in \overline{\operatorname{conv}}^{weak^*}(E_{B_{X^*}})$ there exists $\left\{\displaystyle{\sum_{i=1}^k} \lambda_i^{n}f_i\right\}_{n\in\mathbb{N}}$ such that $\displaystyle{\sum_{i=1}^k} \lambda_i^{n}f_i\xrightarrow{weak^*} f$, where $\lambda_i^{n}\in [0, 1]$ and $\displaystyle{\sum_{i=1}^k} \lambda_i^{n}=1$. Is this correct?
$\textbf{(2)}$ If it happens either way then what can be the form of the limit point $f$?
$\textbf{(2.1)}$ I am not getting the idea of limit of a sequence from convex hull of a set. Is it an infinite convex combination of the extreme points of $B_{X^*}$? (Even I do not know if there is any concept of infinite convex combination)
Please help me with an elaborate explanation with a possible example. Any kind of help is appreciated. Thank you in advance.