-1

I think $Y$ is of a discrete distribution since it takes only an integer and I tried to use the cumulative distribution $X$ to find the distribution of $Y$ but it seems not possible.

How should I approach this?

1 Answers1

2

Let $X \sim Exp(\lambda),$ so that $X$ is distributed according to the pdf $$f_\lambda(x) = \lambda e^{- \lambda x} \chi_{[0, \infty)}(x)$$ and $Y := \lfloor X \rfloor.$ Then $$\mathbb{P}(Y = k) = \mathbb{P}(k \leq X < k + 1) = \int_k^{k + 1} f_\lambda(x) dx = e^{- \lambda k} - e^{- \lambda(k + 1)} = e^{- \lambda k}(1 - e^{- \lambda}).$$ I hope this helps. :)