I'm very lost with the following problem:
Consider $f=(f_1,f_2,f_3)\in\mathcal{C}(\mathbb{R}^3,\mathbb{R}^3)$ such that $f(0,0,0)=(0,0,0)$ and \begin{equation} x_1f_1+x_2f_2+x_3f_3<0 \tag{*} \end{equation} for all $(x_1,x_2,x_2)\in\mathbb{R}^3\backslash\{ (0,0,0)\}$. Prove that the $(0,0,0)$ is the unique equilibrium point of $f$, and its basin of attraction is all $\mathbb{R}^3$.
I have started my course of dynamical systems recently and I find this problem in my practice list of exercises. My problem is that I don't understand very well what does it means that and equilibrium point of a function. I find in my notes the definition of equilibrium point, but for a differential equation $x'=f(x)$. It means to say that I need to find the equilibria of the system $$ \begin{bmatrix} x_1 \\ x_2 \\ x_3 \end{bmatrix}'=\begin{bmatrix} f_1 \\ f_2 \\ f_3 \end{bmatrix} \ ? $$
If so, how does the condition $(*)$ help me? And finally, how it is obtained his basin of attraction from this?
I appreciate your help a lot.