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Two answers here present two very different approaches to motivating ideals.

The first presents the historical motivation for ideals, namely Kummer's idea that in some rings like $\mathbb Z[\sqrt{-5}]$ there are somehow "ideal numbers" that allow us to factor products like $2 \cdot 3 = 6 = (1+\sqrt{-5})(1-\sqrt{-5})$ further, and more importantly, uniquely.

The second presents the completely abstract construction of an ideal $I$ of ring $R$ to be exactly a subset that $a \sim b \iff a-b\in I$ is an equivalence relation s.t. $R/{\sim}$ inherits the ring structure of $R$; or as that answer put it, "Equations in $R$ give corresponding equations between equivalence classes in $R/{\sim}$". An answer here phrased this quotient idea as "You can think of ideals as subsets that behave similarly to zero".

Again in Intuition behind "ideal", Qiaochu Yuan says "To me ideals are kernels of ring homomorphisms". This point of view is very connected to the quotient point of view presented above, essentially by the 1st isomorphism theorem. It also makes rigorous the above idea that "ideals are subsets that behave similarly to zero", since kernels are literally the set of elements that get mapped to $0$ by a ring homomorphism.


My question is how to connect this latter, more "abstract" point of view with the historical/Kummer-Dedekind point of view? I don't really have a good intuition/picture for why the set of all elements "divisible by some (ideal) number" should be exactly a subset of elements $S$ s.t. we can "do exactly the same kind of arithmetic" with cosets $\{r+S\}_{r\in R}$ as we can with elements $\{r\}_{r\in R}$.

user26857
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D.R.
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  • I'd not want to think of ideals as things that are "similar to $0$", but, rather, that they can be kernels of homomorphisms. After all, prime numbers (which generate interesting ideals) are not really "similar to $0$" in most ways...? – paul garrett Apr 07 '22 at 23:06
  • @paulgarrett sure; I just wrote that since I'm trying to tie together all the answers on this site for the question "what are ideals" – D.R. Apr 07 '22 at 23:11

2 Answers2

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Your comment that the correct notion of an ideal was not originally designed for forming the quotient of a ring is off the mark. In fact, this was precisely the rationale behind Kummer's introduction of ideal numbers: although there are no prime factors of $3$ in ${\mathbb Z}[\sqrt{-5}]$, Kummer could easily define residue classes modulo "ideal primes"; his main task was showing that these ideal primes could be multiplied in a coherent way. See https://arxiv.org/abs/1108.6066 . If we look at Kummer's theory from our point of view, his ideal numbers are homomorphisms from the ring of integers into finite fields (which he did not know yet, so he had to work his way around them by looking at the decomposition fields); Dedekind's ideals are simply the kernels of Kummer's ring homomorphisms.

Edit. The following is copied more or less from my book on quadratic number fields:

Consider the ring $R = {\mathbb Z}[\sqrt{-5}\,]$. The elements $2$ and $3$ are irreducible in $R$, mbut not prime. If there was an element $\pi$ of norm $2$, then we could consider the residue class ring of $R$ modulo $\pi$; this quotient ring would have two elements, because it can be shown that the number of residue classes modulo an element of $R$ is equal to its norm.

Reduction modulo $\pi$ thus would give us a ring homomorphism $f: R \rightarrow {\mathbb Z}/2{\mathbb Z}$. Kummer realized that such a ring homomorphism exists even when there is no element of norm $2$. In fact, all we have to do is set $f(a+b\sqrt{-5}\,) = a+b+2{\mathbb Z}$. Thus although there is no prime element $\pi$ of norm $2$, we can work modulo $\pi$ by simply applying $f$. Such ring homomorphisms (or, less anachronistically, such procedures for attaching a residue class to each element) were called ideal primes by Kummer.

In the case of ideal primes of norm $3$ there are two ring homomorphisms $\kappa_3$ and $\kappa_3'$ to ${\mathbb Z}/3{\mathbb Z}$, and they are defined by $\kappa_3(a+b\sqrt{-5}\,) = a+b+3{\mathbb Z}$ and $\kappa_3'(a+b\sqrt{-5}\,) = a-b+3{\mathbb Z}$. The kernel of $\kappa_3$ consists of all ${\mathbb Z}$-linear combinations of $1-\sqrt{-5}$ and $3$; but this is the ideal $(1-\sqrt{-5}, 3)$.

  • this looks along the lines of what I'm looking for; do you mind elaborating on your statement 'Kummer could easily define residue classes modulo "ideal primes"', and how exactly one "translates" between Kummer's ideal numbers and homomorphisms into finite fields? I assume the answer to the latter question has to do with Jacobi maps mentioned in the linked Arxiv paper, but I would appreciate if you could provide some context/summary/overview, perhaps from a modern point of view, just so I can orient myself. – D.R. Apr 08 '22 at 06:42
  • sorry to bother again, but could you write out more explicitly your concrete example $3\in \mathbb Z[\sqrt{-5}]$ and Kummer's residue classes modulo "ideal primes" in $\mathbb Z[\sqrt{-5}]$, and how Kummer's theory for this concrete example can be phrased as a homomorphism from $\mathbb Z[\sqrt{-5}]$ to some finite field? I've tried reading your paper, but it mostly seems to focus on the cyclotomic case, and introduces quite a lot of concepts/machinery in the later sections. Hopefully a more basic concrete computational example can serve as a guide to the more general abstract situation? – D.R. Apr 09 '22 at 06:58
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In elementary number theory you study arithmetic mod $n$. That's arithmetic in the ring $\mathbb{Z}_n$ which is precisely the quotient ring $\mathbb{Z}/n\mathbb{Z}$, where $n\mathbb{Z} = \langle n\rangle $ is the ideal generated by $n$. That quotient is particularly nice when $n$ is prime: it's a field.

In rings of algebraic numbers like $\mathbb{Z}[\sqrt{5}]$ there are ideals that are not principal - that don't have a single generator. But you can still get lots of good number theory by studying the modular arithmetic of the rings you get by taking the quotient by an ideal. The quotient by a prime ideal need not be a field but it is an integral domains.

Ethan Bolker
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  • yes, I am aware. My question was more along the lines of "why do we get lots of good number theory by studying the modular arithmetic of the rings you get by taking the quotient by an ideal", if one only has the point of view that ideals are the abstract objects that allow cosets to inherit the original ring operations? – D.R. Apr 07 '22 at 23:05
  • Your "why?" vergies on philosophical. Modular arithmetic on integers helps you learn things about the ordinary integers you are interested in: Gauss used it before we formulated it abstractly as arithmetic on cosets. Coset arithmetic was not an out of nowhere abstraction that turned out to match what number theorists did. It was codified and generalized because its less formal precursor was useful. The generalization to rings of algebraic numbers was itself invented in order to shed light on the ordinary integers. – Ethan Bolker Apr 07 '22 at 23:57
  • I guess my main question is why is it the case that this "experimentally constructed" notion of ideal, done through many years of trial and error, finally being put into a rigorous definition by Dedekind, is EXACTLY the correct notion for forming the quotient of a ring; a purpose that the idea of "ideal" was not originally designed for. I feel that this surely can not be a coincidence! I feel there must be some point of view in which these two "uses" of ideals come from the same core underlying seed. – D.R. Apr 08 '22 at 05:32