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Let $R$ be a commutative ring.

Introduce equivalent relation in the set of all prime elements of $R$ (we call this set $P$).

$p_1\sim p_2$ if only if $p_1$ and $p_2$ are associate ($p_1|p_2$ and $p_2|p_1$).

Then, I want determine all $R$ which satisfies
(★) $P/\sim$ has only one element.

For example, when $R=\Bbb{Z}_p$, $P=\{pu|u \text{ is a unit element of }R\}$, $P/\sim=\{[p]\}$, so $R=\Bbb{Z}_p$ satisfies (★).

I couldn't come up with another ring which satisfies (★), and I wonder this is essential characteristic of ring of $p$ adic integers, like saying ,'$\Bbb{Z}_p$ is a ring with only one prime (element), $p$'.

user26857
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Poitou-Tate
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3 Answers3

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Here's an example that is a domain but not a DVR: let $R$ be a valuation ring with value group $\Bbb Z \times \Bbb Z$ with lexicographic order. An element is prime iff it has valuation $(0,1)$ and all those elements are associate.

Lukas Heger
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There are a lot of such rings: every discrete valuation ring has the property (*). For example every localization of the polynomial ring $K[X]$ over a field $K$ with respect to any prime polynomial $p\in K[X]$.

Hagen Knaf
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As Hagen Knaf's answer says, any DVR (almost by definition) is an example of this. Quotients of DVRs give more examples. Polynomial rings over (e.g.) $\mathbb Z/p^n$ ($n \ge 2$) give more noetherian examples which are not domains.

Lukas Heger's answer gives other examples among domains which are not noetherian.

Another example among noetherian domains was given by user reuns in answer to Noetherian domain with unique principal prime ideal that is not a DVR.

Another example, which is neither a domain nor noetherian, was given here: https://mathoverflow.net/a/155250/27465.