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Suppose for $x\in \mathbb{R}^m$ we have a well behaved differential inclusion $\dot x \in F(x)$, where $F(x)$ is a Marchaud map, i.e. u.s.c. with compact convex values and linear growth condition: there exists $c>0$ s.t. $$\sup\{\|y\|:\, y\in F(x) \}\le c(1+\|x\|)$$ for all $x$. So absolutely continuous solutions exist, but may not be unique. We also assume $F$ is $C^1$ whenever it is single-valued.

Now suppose there is a rest point $x^*$ in a neighborhood $U$, s.t. $F(x)$ is single valued on that neighborhood, $F(x^*)=0$, and $x^*$ is hyperbolic. Can we still apply Hartman-Grobman in a neighborhood around that rest point? I would think yes, since the construction is local, but I'm not sure if somehow the non-uniqueness of solutions may give us an issue. Could someone give me a hint please?

Clempe
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  • It seems that glancing over the proof of Hartman-Grobman is enough.. using a cutoff function I don't think I need to care about any properties of $F(x)$ outside of the neighborhood $U$. – Clempe Nov 25 '21 at 22:31

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