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I'm having trouble with the proof of the next statement:

Let $U\subset \mathbb{C}$ be open and connected. If $f$ is defined in $U$ and is holomorphic, and the set of its zeros have and accumulation point, then $f$ is constant on $U$.

I know how to prove this when that accumulation point is in $U$, but I don't know what to do in the other case. Hope you can help me, please.

Thank you.

jamie
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1 Answers1

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It's not true. For example, $\sin(1/z)$ with $U = \mathbb C \backslash \{0\}$.

Robert Israel
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