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This is a question that I derived for a long time ago. It asks if we draw a triangle in a unit circle does all arc lengths $(\alpha ,\beta ,\theta)$ and sides of triangle $(a,b,c)$ can be rational numbers? Intuitively I believe that the rationality does not hold but I can't derive a proof. Do you have any ideas?

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newzad
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1 Answers1

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$\alpha + \beta + \theta = 2 \pi$, so they can't all be rational.


You might want to write the arc lengths as $\alpha \pi, \beta \pi, \theta \pi$, in which case $\alpha + \beta + \gamma = 2$, and it gets slightly more interesting.

The answer is still no.

(WLOG, we have $0 \leq \alpha, \beta, \gamma \leq 2$.) This arises because $a= 2| \sin \frac{\alpha\pi}{2}|$, which is rational if and only if $\frac{\alpha}{2} \in \{ 0, \frac{1}{6} ,\frac{1}{2}, \frac{5}{6}, 1\} $. This is known as Niven's Theorem.

The only way to get $\frac{\alpha}{2} + \frac {\beta}{2} + \frac{\gamma}{2} = 1$ is then to require that $\alpha\beta\gamma=0$ (slight checking involved), which is the degenerate cases (that I'm ignoring). These cases correspond to either having a point on the circumference, or a chord of the circle.

Calvin Lin
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