While solving some linear equation I Stopped on the following: How to rearrange coefficients and constants to find integer solutions for: $2xy+3x+3y=106$. If we take $x$ as a common factor from the first two terms then we get: $x(2y+3)+3y=106$. Any suggestion how to go farther..
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$$4xy+6x+6y= 212$$ $$4xy+6x+6y +9= 221$$ $$ (2x+3)(2y+3) = 221 = 17 \cdot 13$$
Will Jagy
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Please strive not to add more dupe answers to dupes of FAQs. – Bill Dubuque Jan 26 '21 at 08:29