Let $L\subset \mathbb C^3$ be the line defined by $x=y=0$, and $p\in L$ the point defined by $x=y=z=0$. Let's consider the blowup of $\mathbb C^3$ at $p$ and then blow up the strict transform of $L$ and denote the new space as $X$.
We can also consider blowup of $\mathbb C^3$ along $L$ and then blow up the preimage of $p$ and denote the new space as $Y$. The two spaces are not the same because the fibers over $p$ are not Edited: The fibers of $X$ and $Y$ over $p$ are the same: On one side, it is the blowup a point on $\mathbb P^2$, while on the other side, it can be viewed as a $\mathbb P^1$-bundle over $\mathbb P^1$.
Question 1: Are $X$ and $Y$ isomorphic?
According to Hartshorne II. Theorem 7.17, $$X\to \mathbb C^3$$ is a blowup of some ideal $I$ on $\mathbb C^3$, and the same for $Y$ and we denote the corresponding ideal as $J$.
Question 2: How to determine the ideals $I$ and $J$ explicitly?
It is elementary to check that both $I$ and $J$ are contained in the ideal $(x,y)$ of $L$, reduced on $L\setminus \{p\}$ and non-reduced at $p$ (otherwise, they would be isomorphic to $Bl_{L}\mathbb C^3$), but they have different non-reduced structure at $p$.
$(x^2,y^2,xy,xz,yz)$ as Youngsu suggested is probably the first ideal to consider that is supported on $L$ and non-reduced only at $p$, but currently, I can't determine it is $I$ or $J$, or perhaps neither of them.
How to find such $I$ and $J$ explicitly? Thanks in advance for any help.