Show that $C^1[0,1]$ is not a banach space using the closed graph theory with the maximum norm. First, look at the derivative operator: $D:C^1[0,1]\to C[0,1]$, $D(f)=f'$.
We can check that $D$ is linear and not bounded (by taking an example such as a polynomial $x^{n+1}$). Thus $D$ is not continuos. I'm not sure, if it is possible to show that $D$ has a closed graph (a linear map $T:X\to Y$ has a closed graph if $x_n\subset X$ such that $x_n\to x$ and $T_{x_n}\to y$ then $Tx=y$).So if by contradiction, we assume that $C^1[0,1]$ is banach with the sup norm, then get by the closed graph theory that $D$ is continuos, which is not true according to what we've said.