How many 3-colorings of cube's faces exist if we consider two colorings the same iff it's possible to rotate and/or mirror the cube such that one coloring goes to another?
I do know a similar question considering only the rotations was asked here. I do understand where the solution comes from: Burnside's lemma and the geometrical classification of cube rotations (by face, by edge, by vertex, etc). But I can't seem to construct a convenient geometrical classification of all the symmetries (is there really a sensible geometrical approach to this problem???)
I sense that the full symmetry group of a cube is $S_4 \times \mathbb Z_2$ since we can fix an arbitrary mirroring and combine it with all the rotations of the cube (which form a group isomorphic to $S_4$). I have heard of a solution which uses an embedding $S_4 \times \mathbb Z_2 \rightarrow S_6$ which "realizes all cube symmetries in permutations of cube's faces". I though have no idea how to build such an embedding and how can it help?
Basically I am looking for any approach to this problem which doesn't involve calculating $\text{Fix}(g)$ for all of the 48 cube symmetries $g$ separately and plugging it in Burnside's lemma (this is going to be on a test with limited time, so that is not acceptable).
