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If $$ is a convex polygon and is divided into $ − 2$ triangles with diagonals. What is the maximum number of acute triangles you can have?

I did not understand the part of triangles with diagonals, but fortunately they helped me in this post, But no matter how much I look for how to solve the problem, it gets more complicated, mainly because of the factor of how to take the consideration that the angle is acute

David G. Stork
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Haus
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    Will it help you https://math.stackexchange.com/questions/1446438/how-many-triangles-can-be-formed-by-the-vertices-of-a-regular-polygon-of-n-sid/1446470#1446470 ? – Harish Chandra Rajpoot Jun 23 '20 at 05:48
  • I do not know if I am misunderstanding the question, but, could not the n-2 acute triangles be at first? – Haus Jun 23 '20 at 06:54
  • Is $P$ a regular n-gon or can it be any convex polygon with n sides? – Jaap Scherphuis Jun 23 '20 at 08:08
  • The information only tells me that it is a simple polygon, not that it has to be regular. So I think it's any convex polygon with n sides – Haus Jun 23 '20 at 17:49
  • @Harish I have reviewed what you have attached to me and today I have been thinking. I think the answer would be that the maximum of acute triangles is n-2 ?, based on what I have reviewed, it seems to me that it is the answer; but I would really appreciate it if you correct me, thanks. – Haus Jun 24 '20 at 04:34

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