Can you please see the following question : Let X be any set with three elements or more and B be the collection of all two element subset of X . Show that B is not a base for any topology >>
I think on it as the following : since there are more than three elements in X then set B must have two subset of X of the form {x,y} , {y,z} suppose by contrary B is base then {x,y} , {y,z} are open subset their intersection {y} is open but it can not generated from B so contradiction ..
is it true ?