I am having trouble representing this following list of numbers mathematically ,
$$ A_{n1}= (2*3) $$ $$=\color{red}{6}$$ $$ A_{n2} = (2*3)\, , (2*4)\, , (3*4)\, , (2*3*4) $$ $$= \color{red}{6,8,12,24} $$ $$ A_{n3} = (2*3),(2*4),(2*5),(3*4),(3*5),(4*5),(2*3*4),(2*3*5),(2*4*5),(3*4*5),(2*3*4*5) $$ $$ = \color{red}{6,8,10,12,15,20,24,30,40,60,120} $$ $$ A_{n4} = \begin{matrix} (2*3)&(2*3*4)&(2*3*4*5)&(2*3*4*5*6)\\ (2*4)&(2*3*5)&(2*3*4*6)\\ (2*5)&(2*3*6)&(2*3*5*6)\\ (2*6)&(2*4*5)&(2*4*5*6)\\ (3*4)&(2*4*6)&(3*4*5*6)\\ (3*5)&(2*5*6)&\\ (3*6)&(3*4*5)&\\ (4*5)&(3*4*6)&\\ (4*6)&(3*5*6)&\\ (5*6)&(4*5*6)&\\ \end{matrix}$$
$$ =\color{red}{6,8,10,12,12,15,18,20,24,24,30,30,36,40,48,60,60,72,90,120,120,144,180,240,360,720}$$
**Please note that the $A{n4}$ is not a matrix even though it resembles one (written as one) , i did it this way so that you could see where the terms are coming from.
I have read on combinatorics , binomial theorem and others and still am having trouble.
My hopes are to represent each $A_{n}$ mathematically either as a sum , product or any kind of function where i can plug in a value and obtain a term perhaps such as :
$$ F(A_{nK},T)=F(A_{2},3) = (3*4) = 12 $$
This has stumped me for a few days.
I thank you kindly for your help and time with this problem.