Suppose $M$ is a smooth manifold with a smooth vector field $X$ on it. If $X$ is not a complete vector field (a complete vector field is one for which all integral curves exist for all time) is it possible to embed it in another smooth manifold and extend $X$ to a complete vector field on the new manifold? More precisely, can one find a smooth manifold $N$, a complete vector field $Y$ on $N$, and a smooth embedding $F : M \to N$ such that $F_*X = Y$, i.e. for all $p \in M$, we have $dF_p (X_p) = Y_{F (p)}$?
For example, if $M = (0, 1) \subset \mathbb R$ and $X = \partial_x$ then clearly $X$ is not complete, but $M$ embeds inside $N = \mathbb R$ with the extension $Y = \partial_x$, which is complete.
I haven't thought about these things in a long time, though.
– Alekos Robotis Mar 28 '20 at 21:54