Let $f:[0,1]$ be a real, Lebesgue/Riemann integrable, Lipschitz continuous and differentiable almost everywhere function. Is $f'$ Lebesgue integrable?
On one hand, $f'$ can be undefined for some points on $[0,1]$. On the other hand, the set where $f'$ is not defined has measure zero.
I think there is no sense to say that $f'$ is Lebesgue integrable is $\lvert f'\rvert$ is not defined.