0

In the book titled: "Combinatorics - A guided tour', by David Mazur; there is in chapter 5, titled: 'Counting Under Equivalence', a diagram showing up $4$ equivalent grids (under rotation) of a $3*3$ square grid, colored using two colors - black, white.

According to me, the diagram's last two grids are flawed, if take grid$1$ or grid $2$ as reference.

To easily explain my doubt, if assume that the grid has following structure:

$A1 \ \ A2 \ \ A3$
$B1 \ \ B2 \ \ B3$
$C1 \ \ C2 \ \ C3$

Then the $4$ grids are having colors as:
$\ Grid 1 \ \ \ \ \ \ \ \ \ \ Grid 2 \ \ \ \ \ \ \ Grid 3 \ \ \ \ \ \ \ \ \ Grid4$
$W \ B \ \ W \ \ \ \ W \ W \ W \ \ \ \ B \ W \ W\ \ \ \ W \ W \ B$
$W \ W \ W\ \ \ \ W \ W \ B \ \ \ \ W \ W \ W\ \ \ \ B \ W \ W$
$W \ W \ B \ \ \ \ \ B \ W \ W \ \ \ \ W \ B \ W\ \ \ \ W \ W \ W$

As per me, the $4$ grids that are equivalent under rotation,
should have different colors in the last two grids,
as shown below:
$\ Grid 1 \ \ \ \ \ \ \ \ \ \ Grid 2 \ \ \ \ \ \ \ Grid 3 \ \ \ \ \ \ \ \ \ Grid4$
$W \ B \ \ W \ \ \ \ W \ W \ W \ \ \ \ B \ W \ W\ \ \ \ W \ W \ B$
$W \ W \ W\ \ \ \ W \ W \ B \ \ \ \ W \ W \ B\ \ \ \ W \ W \ W$
$W \ W \ B \ \ \ \ \ B \ W \ W \ \ \ \ W \ W \ W\ \ \ \ W \ B \ W$

The image

jiten
  • 4,960

1 Answers1

1
  • The third picture can be obtained by rotating the second picture clockwise $90^\circ$.

  • The fourth picture can be obtained by rotating the third picture clockwise $90^\circ$.

Siong Thye Goh
  • 153,832