How to find an example: a convergence series $\sum a_n$, a divergent series $\sum b_n$, whose Cauchy product $\sum c_n$ with $c_n=\sum_{i+j=n}a_ib_j$ is convergent? Is there a simple example?
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2What about $a_n = 0, b_n = 1/n$? – Martin R Feb 20 '20 at 10:08
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@MartinR Thanks. Is there any more not such trivial example? – xldd Feb 20 '20 at 10:11
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I know a non trivial example where you have two divergent series and their Cauchy product is convergent. If interested let me know and I will post it – Luca Goldoni Ph.D. Feb 20 '20 at 17:48
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@LucaGoldoniPh.D.: Such examples are already given here: https://math.stackexchange.com/q/2293968/42969 and here: https://math.stackexchange.com/q/3314213/42969. – Martin R Feb 21 '20 at 07:44
2 Answers
Let be $a_n$ such that $a_{2k}=a_{2k+1}$ for every $k=0,1,2...$. Let be $b_k=(-1)^k$. Then it is $$ c_{2n} = \sum\limits_{k = 0}^{2n} {a_k } b_{2n - k} = a_0 - a_1 + \cdots - a_{2n - 1} + a_{2n} $$ and $$ c_{2n + 1} = \sum\limits_{k = 0}^{2n + 1} {a_k } b_{2n - k} = - a_0 + a_1 + \cdots - a_{2n} + a_{2n + 1} $$ It follows that $$ s_{2n} = \sum\limits_{k = 0}^{2n} {c_k = a_0 } + a_2 + \cdots a_{2n} $$ and $$ s_{2n + 1} = \sum\limits_{k = 0}^{2n + 1} {c_k = a_1 } + a_3 + \cdots a_{2n + 1} $$ If the series $ \sum\limits_{k = 0}^{ + \infty } {a_k } $ is convergent we get the required example. For instance we can choose $a_0=a_1=1$, $a_2=a_3=1/2$, $a_4=a_5=1/2^2$ and so on.
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HINT.- Take a limit of the form $0\cdot\infty$ and develop the corresponding Taylor series.
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