Compute the following sum in terms of an expression having only one binomial coefficient: For $m,n \in\mathbb{N}$
$$\sum_{k\leq m}(-1)^k {n\choose k}$$
I have started with
$$\sum_{k\leq m}(-1)^k {n\choose k} = \sum_{k\leq m}(-1)^k \frac {n!}{k!(n-k)!}$$
But I am having trouble proceeding from there! I feel as if I am doing something wrong and am not able to find any results that could help. If I could get any hints that would be ideal! Thank you!