Question While solving a non-linear partial differential equation, i am stuck to a problem $$z^2(x^2p^2+q^2)=1$$ And let $$F=z^2(x^2p^2+q^2)-1$$ Where $p=\frac{\partial z}{\partial x}$ And $q= \frac{\partial z}{\partial y}$
my approach From Charpit method $$\frac{dx}{F_p}=\frac{dy}{F_q}=\frac{dz}{pF_p+qF_q}= \frac{-dp}{F_x+pF_z}=\frac{-dq}{F_y+qF_q}$$
$$\frac{dx}{2px^2z^2}=\frac{dy}{2qz^2}=\frac{dz}{2p^2x^2z^2+2q^2z^2}=\frac{-dp}{2xp^2z^2+2pz(x^2p^2+q^2)}=\frac{-dq}{2zq(x^2p^2+q^2)}$$
The solution of the pde is given by $$dz=pdx+qdy$$ My problem is, i am unable to seperate the functions for further solution. Any subtle hints are highly apperciated.