Just out of curiosity, can this be done? For the euclidian topology.
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4Under what sense of dimension? The Cantor set $K \subset [0, 1] \subset \mathbb{R}^2$ is closed and not really 1-dimensional. – Unit Aug 06 '19 at 23:51
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thank you @Michael, didn't find that question, that was what I was looking for! – João Dionísio Aug 07 '19 at 00:12
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@J.Dionisio : Thanks for the feedback. Apparently someone with the power to do so deleted my comment that identified the prior question, then, the link I gave was included above as if I never existed! – Michael Aug 07 '19 at 05:44