$\newcommand{\h}{\mathcal{O}}$$\newcommand{\sep}{\mathrm{sep}}$$\newcommand{\Gal}{\mathrm{Gal}}$$\newcommand{\ov}[1]{\overline{#1}}$$\newcommand{\Spec}{\mathrm{Spec}}$
Disclaimer: Of course, none of the below is original. I don't remember where I first learned it (it was almost certainly something Brian Conrad wrote, but I can't find it--it might be something he posted on MO?).
Setup:
Let $X$ be any Dedekind scheme. By defintion (for me) this means that $X$ is an integral normal Noetherian scheme of dimension $1$ (so locally the spectrum of a Dedekind domain). Let us set $K:=K(X)$. Note that for each point $x\in X$ we can define an inertia subgroup at $x$, denoted $I_x$, as follows. Let $\h_{X,\ov{x}}$ be the strict Henselization of $X$ at $\ov{x}:\Spec(k(x)^\sep)\to X$ (see this for more detail). Note that we can embed $\h_{X,\ov{x}}$ into $K^\sep$ essentially as follows. Choose a valuation $v'$ of $K^\sep$ lying over $v_x$. Then, take the union of the valuation rings $\{x\in F:v'(x)\geqslant 0\}$ as $L$ travels over the finite subextensions of $K^\sep/K$ such that $v'$ (restricted to that extension) is unramified over $K$. Let $L_x:=\mathrm{Frac}(\h_{X,\ov{x}})$. We then set $I_x:=\Gal(K^\sep/L_x)$. Note that $\Gal(K^\sep/K)/I_x\cong \Gal(k(x)^\sep/k(x)$.
So, in reality we won't explicitly parameterize all etale covers. Instead, we'll virtually parameterize all etale maps. Less cryptically, let us now suppose that $Y\to X$ is an etale morphism. Then, we know that $Y\to X$ is locally quasi-finite--there is an open cover $\{Y_i\}$ of $Y$ such that $Y_i\to X$ s quasi-finite. In particular, every etale map $Y\to X$ has a refinement (in the big Zariski site) by a cover of the form $\displaystyle \bigsqcup_i Y_i\to X$ with $Y_i\to X$ quasi-finite. Thus, for all intents and purposes it's really enough to describe the category $\mathscr{C}$ of all quasi-finite etale maps $U\to X$.
Let us make the further following reduction. Namely, note that if $Y\to X$ is quasi-finite then $Y_K\to\mathrm{Spec}(K)$ is a finite etale $K$-scheme. Indeed, we know that every etale scheme over $\mathrm{Spec}(K)$ is a disjoint union of spectra of finite separable extensions of $K$ (e.g. see this). Since $Y_K$ is quasi-finite it must be a finite disjoint union, and thus a finite etale cover.
By the 'spreading out principle' this implies that there exists some open subscheme $U$ of $X$ such that $Y_U\to U$ is finite etale. Let us set $\mathscr{C}_U$ to be the category of quasi-finite etale maps $Y\to X$ such that $Y_U\to U$ is finite. Then, what we will actually do here is give a fairly easy way to 'paramaterize' the category $\mathscr{C}_U$.
Description of $\mathscr{C}_U$
Let us take an object $Y\to X$ of $\mathscr{C}_U$. We shall essentially claim is that we can somehow capture $Y$ by the finite etale cover $Y_U\to U$ and the 'straggler fibers' over the points in $Z:=X-U$. moreover, we shall claim that both pieces of these data can be described in terms of Galois sets.
Let us begin by noting that if $Y\to X$ is in $\mathscr{C}_U$ the since $U$ is normal we know that $Y_U$ is normal. And, in fact, it's pretty easy to see that $Y_U$ is actually just the normalization of $X$ in $Y_K$. Thus, we see that $Y_U$ is actually determined from $Y_K$ which is determined by the finite (discrete) $\Gal(K^\sep/K)$-set $Y(K^\sep)$ which is unramified along $U$. Recall that a $\Gal(K^\sep/K)$-set $T$ is called unramified at $x$ if $I_x$ acts trivially on it, and that it's unramified along $U$ if its unramified at every $x\in U$.
In fact, what we have just described is the following well-known result:
Fact 1: The association $V\mapsto V(K^\sep)$ is an equivalence of categories from the category $\mathsf{Fet}(U)$ of finite etale covers of $U$ to the set of finite discrete $\Gal(K^\sep/K)$-sets unramified along $U$.
So, this accounts for $Y_U\to U$, but what about these straggler fibers $Y_x$ for $x\in Z:=X-U$?
Well, note that for each $x\in Z$ that we have a natural inclusion $Y(k(x)^\sep)\hookrightarrow Y(K^\sep)$. Indeed, since $Y_{\Spec(\h_{X,\ov{x}})}\to \Spec(\h_{X,\ov{x}})$ is etale, we can use Hensel's lemma to say that $Y(k(x)^\sep)=Y(\h_{X,\ov{x}})$. Since $\h_{X,\ov{x}}\hookrightarrow K^\sep$ (by the discussion at the beginning of the setup) this gives us a natural map $Y(k(x)^\sep)\to Y(K^\sep)$ which is easily seen to be injective. Moreover, since $I_x$ naturally acts trivially on $Y(k(x)^\sep)$ (by definition) we see that $Y(k(x)^\sep)$ naturally lands in $Y(K^\sep)^{I_x}$.
Note that since $I_x$ acts trivially on $Y(K^\sep)^{I_x}$ that $\Gal(k(x)^\sep/k(x)$ acts on $Y(K^\sep)^{I_x}$ and, in fact, the inclusion $Y(k(x)^\sep)\hookrightarrow Y(K^\sep)^{I_x}$ is $\Gal(k(x)^\sep/k(x)$-equivariant.
The main result is then the following:
Theorem: The association $Y\mapsto (Y(K^\sep),\{Y(k(x)^\sep)\}_{x\in Z})$ is an equivalence of categories from $\mathscr{C}_U$ to the category
of tuples $(T,\{T_x\})$ where $T$ is a finite discrete
$\Gal(K^\sep/K)$-set and $T_x$ is a $\Gal(k(x)^\sep/k(x))$-stable
subset of $T^{I_x}$. Moreover, $T_x=T^{I_x}$ if and only if the associated quasi-finite etale scheme $Y\to X$ is finite etale in some open neigborhood of $X$.
So we see that $\mathscr{C}_U$ is parameterized by some concrete sets of Galois theoretic data.
Will add example with $\mathbb{A}^1_k$ later
