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It's easy to show that $G$ is abelian if $a^2=e.$

Can't seem to figure out how to prove/disprove this.

PrincessEev
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1 Answers1

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The standard counterexample is the group of matrices of the form $$\pmatrix{1&a&b\\0&1&c\\0&0&1}$$ over the field of three elements.

Angina Seng
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