Are all finite groups isomorphic to the multiplicative group of a ring. If I know the multiplicative group, can I define the addition as a function of 2 variables for all groups?
Asked
Active
Viewed 155 times
2
-
5A ring doesn't have a multiplicative group. It does have a multiplicative group of units. – Arthur Feb 24 '19 at 12:11
-
2There's ambiguity on whether you want $G$ to embed as a subgroup of $R^\times$, or to be isomorphic to $R^\times$. – YCor Feb 24 '19 at 12:17
-
1I wanted it to be isomorphic to multiplicative group of units. – alper akyuz Feb 24 '19 at 12:22